intercooling
Originally Posted by civbuster
Lets say you are running no turbo (14.7 psi @ sea level / 101.3 kPa) w/ a 2.4L ralliart engine. This means the temp going into your engine would be the same as the outside air, lets say a balmy 80F ( 299.8 K). Now bump the turbo up to 6psi; now the pressure is 20.7 psi (142.7 kPa), still w/ 2.4L. so now some physics...
(101.3 kPa * 2.4L) / 299.8 K = (142.7 kPa * 2.4L) / x K
solve for x
x = 422.3 K = 300.47 F
End result, a not so balmy 300F
(101.3 kPa * 2.4L) / 299.8 K = (142.7 kPa * 2.4L) / x K
solve for x
x = 422.3 K = 300.47 F
End result, a not so balmy 300F
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