what would the octane be when mixing 94 and 104 octane 50/50 mix

 

99oct

Tough math, I know...

 

(94octane*6/12gal)+(104octane*6/12gal)=99octane

 

Do this in order -

1. 94(octane rating) x 6(this is the # of gallons of that octane)=564
2. 104(octane rating) x 6(this is the # of gallons of that octane)=624
3. Add 564+624=1188
4. Divide 1188 by 12 (which is the total # of gallons of gas)
5. Answer=99 octane

All you are doing is just calculating an average.

Slowcar's formula is perfect...I just decided to explain it the long way.

 

wartalon u must be god

 

So half, half???

 

simpler way:

take the difference in octane (10), divide it by 2, and you get 5. now add that to 94, or subtract it from 104, and you get 99! ta-da!

why i posted that i have no idea. then again i have no idea why this thread was started either.

 

What you mean to say is take the average of the two: (104+99)/2.

Markeddy's explanation, although lengthy, is better in this case, just in case any future mixing is not 50/50, which is much more likely anyway. It's all basic math. I think steelcityevo just needs to know that octane rating is directly proportional...