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Box Building?

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Old Dec 3, 2003 | 12:13 PM
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Box Building?

Ok, i am looking into getting a Infinty kappa perfect 10.1D and i was going to build a box for it...well i cant remember how to do the calculations.. i used to know and now its all blanks.... Infinity says the box V=.60ft(cubed). now i know that LxWxH=V but how can i make a box that fits a 10" sub have a volume of .60ft....

i just remembered reading something about there are interior and exterior dimensions or something... could this be for the interior is that y i am having problems????

Please help thanks
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Old Dec 5, 2003 | 11:28 AM
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soooo..... nobody knows???
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Old Dec 5, 2003 | 11:56 AM
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The ideal dimensions would be such that each side of the cube is a golden rectangle. A golden rectangle is one that has lengths of side A and B such that A/B=1.61803. This requires a little bit of math, but when I did this for the box I built for my 10" audiobahn, the sound was incredible. This will give you accoustically the right dimensions so sound waves in the box will not cancel each other out as they bounce around the inner walls. Also to note is that these numbers have to be the inner dimensions of the cube. Don't expect to get exactly this ratio (I didn't), but this is a great starting point. The other question is will this box be sealed or vented. There are other aspects to consider for vented boxes.
hope this helps.
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Old Dec 5, 2003 | 01:02 PM
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the box will be sealed. just to clarify, th sides A and B should be added together to make that.... also, since this is a box, what about the other two sides.... BTW thanks, def the best help so far.
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Old Dec 5, 2003 | 01:54 PM
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They should be divided so the ratio is 1.61803 or .61803 if divided the other way. the ratios I used to calculate the three dimensions were .61803 x 1 x 1.61803. (if I remember correctly) Pick a value for "1" say 7. Then multiply by 1.61803 to get ~11.3263. Then divide 11.3263 by .61803 to get ~18.3265. This gives you a volume of ~1453 in (cubed). which equals .841 ft (cubed). This is a little big for your application, but gives you an idea of how to come up with the numbers. I rounded to the nearest 1/8 inch for my box. Also, check to see if the specs give a range like .6 - .8 ft (cubed). This will make picking values a little easier. Next just add in the thickness of the material (I used 3/4" MDF) to get the outer dimensions.
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Old Dec 5, 2003 | 02:00 PM
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h" X d" X w"/1728= cuft use inside measurments,and give space for the woofer(h X w X d X is in inches)
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Old Dec 5, 2003 | 02:02 PM
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trubidor that gave me a head ache!!
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Old Dec 5, 2003 | 02:06 PM
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I did say it would take some math!
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