EGR elimination !!
No worries, nothing will come loose on this. I removed a part on the other side of the valve, and did not mess with any fasteners, etc. on the manifold side. The spring is normally closed and I dont believe vaccuum would pull it open. If this were the case, there would be nothing stopping it from pulling open right now on your car without modification. Unless it is supposed to open on vaccuum?
On another note, I just had another thought. If you want to try this on your vehicle, you can simply unscrew the four bolts on the motor housing and remount the valve body. No need to take out the screwdrive of the stepper half. I would recommend a peice of tape should be put over the opening so the screwdrive doesnt drive itself out.
On another note, I just had another thought. If you want to try this on your vehicle, you can simply unscrew the four bolts on the motor housing and remount the valve body. No need to take out the screwdrive of the stepper half. I would recommend a peice of tape should be put over the opening so the screwdrive doesnt drive itself out.
i dont think a resistor will work and removing the pintle will still set a cel. If one set of 3 wires controls the stepper motor the other three probably verify the degree the EGR is opening (similar to a tps). If the EGR flappy thing never moves it won't change the potentiometer therefore cel?
there is not potentiometer, whatever the hell that is
You basically need to replicate the EGR valve circuit, the manual says the resistance between 2 and 1 or 3, and 5 and 4 or 6 should be between 20 and 24 ohms, so that's not an issue.
What is the resistance between 1 and 3, and 4 and 6?
If there is no resistance you will need one resistor for pin 2 and one for pin 5, you just connect the wires from pins 3, 12 to the resistor on pin 2 and pins 19 and 26 to the resistor on pin 5 (referenced from the ecu at c-133 as shown.)
If the resistance is 40 to 48 then you need to connect two resistors to pins 2 and 5 going to each of the pins on ecu connector c-133.
either way the resistors have to be between 20 and 24 ohms, radioshack should have something that will work and I positive someone will have even better places to buy from
Edit: It appears your resistance will be between 40 and 48 ohms.

You basically need to replicate the EGR valve circuit, the manual says the resistance between 2 and 1 or 3, and 5 and 4 or 6 should be between 20 and 24 ohms, so that's not an issue.
What is the resistance between 1 and 3, and 4 and 6?
If there is no resistance you will need one resistor for pin 2 and one for pin 5, you just connect the wires from pins 3, 12 to the resistor on pin 2 and pins 19 and 26 to the resistor on pin 5 (referenced from the ecu at c-133 as shown.)
If the resistance is 40 to 48 then you need to connect two resistors to pins 2 and 5 going to each of the pins on ecu connector c-133.
either way the resistors have to be between 20 and 24 ohms, radioshack should have something that will work and I positive someone will have even better places to buy from
Edit: It appears your resistance will be between 40 and 48 ohms.
Last edited by DangerousDan; Jun 7, 2007 at 02:37 PM.
it's in the circuit diagrahms on the manual. MFI system. yeah, you can measure it when it's in hand, I guess wait on drew to come back on. here is all teh MS Paint skilz I will show for today.
it's a circuit, with the pin numbers in black, two or four resistors labeled "R," the top is pin 2 and pin 5 on the egr valve(or on the wiring connector, going to junction s026 (which is the power source from the mfi relay) near the fuse box) the bottom (3, 12, 19, and 26) are the pins on the ECU.ECU PINOUT
Guys- I would not do anything with resistors. You might pull too much current through the ECU.. I understand why you'd think it would work, but I am not comfortable with this and wouldn't try it myself. I believe what you're measuring is the coil in the motor. What the EGR control signal pulses is the driving circuitry. They are not the same. On the picture above (maybe a few pictures above), you'll see at the bottom some circles with "tails" coming out of the left. The left side is what the ECU drives, they are the base of the NPN transistor, allowing current to sink from the collector to emitter, thus turning on the circuit. You can think of them as switches, turning on when voltage is applied to the base (tails) of the trasistors.
The resistance from the base will be different than just throwing some resistors in. The resistors that would be installed as mentioned above would put them in parallel since you're not including an electronic switch. The formula for two transistors in parallel is R = (r1+r2)/(r1xr2) where R = equivalant resistant, r1= resistor1, and r2= resistor2... You can see that the resulting resistance will always be smaller than the lowest value of resistor you utilize.
Let me exxagerate to make it apparant: if you use two resistors, one 10000 ohms, and the other 5 ohms, the resulting resistance would end up being just under 5 ohms.
I suggest that we keep the original stepper motor installed, disconnect from the valve, install the valve on the bung and see if it throws a CEL.. However, another member mentioned that it would. I am going to try to put the modified EGR valve in my car now. I dont know how ambitious I'll be. I'll update in a couple of hours.
The resistance from the base will be different than just throwing some resistors in. The resistors that would be installed as mentioned above would put them in parallel since you're not including an electronic switch. The formula for two transistors in parallel is R = (r1+r2)/(r1xr2) where R = equivalant resistant, r1= resistor1, and r2= resistor2... You can see that the resulting resistance will always be smaller than the lowest value of resistor you utilize.
Let me exxagerate to make it apparant: if you use two resistors, one 10000 ohms, and the other 5 ohms, the resulting resistance would end up being just under 5 ohms.
I suggest that we keep the original stepper motor installed, disconnect from the valve, install the valve on the bung and see if it throws a CEL.. However, another member mentioned that it would. I am going to try to put the modified EGR valve in my car now. I dont know how ambitious I'll be. I'll update in a couple of hours.
So the SAFEST way to do it will be to mechanically cheat lets see your test results. Remember to drive the car cruising at a constant speed.
Again thanks for all the hard work guys...
Again thanks for all the hard work guys...
Guys- I would not do anything with resistors. You might pull too much current through the ECU.. I understand why you'd think it would work, but I am not comfortable with this and wouldn't try it myself. I believe what you're measuring is the coil in the motor. What the EGR control signal pulses is the driving circuitry. They are not the same. On the picture above (maybe a few pictures above), you'll see at the bottom some circles with "tails" coming out of the left. The left side is what the ECU drives, they are the base of the NPN transistor, allowing current to sink from the collector to emitter, thus turning on the circuit. You can think of them as switches, turning on when voltage is applied to the base (tails) of the trasistors.
The resistance from the base will be different than just throwing some resistors in. The resistors that would be installed as mentioned above would put them in parallel since you're not including an electronic switch. The formula for two transistors in parallel is R = (r1+r2)/(r1xr2) where R = equivalant resistant, r1= resistor1, and r2= resistor2... You can see that the resulting resistance will always be smaller than the lowest value of resistor you utilize.
Let me exxagerate to make it apparant: if you use two resistors, one 10000 ohms, and the other 5 ohms, the resulting resistance would end up being just under 5 ohms.
I suggest that we keep the original stepper motor installed, disconnect from the valve, install the valve on the bung and see if it throws a CEL.. However, another member mentioned that it would. I am going to try to put the modified EGR valve in my car now. I dont know how ambitious I'll be. I'll update in a couple of hours.
The resistance from the base will be different than just throwing some resistors in. The resistors that would be installed as mentioned above would put them in parallel since you're not including an electronic switch. The formula for two transistors in parallel is R = (r1+r2)/(r1xr2) where R = equivalant resistant, r1= resistor1, and r2= resistor2... You can see that the resulting resistance will always be smaller than the lowest value of resistor you utilize.
Let me exxagerate to make it apparant: if you use two resistors, one 10000 ohms, and the other 5 ohms, the resulting resistance would end up being just under 5 ohms.
I suggest that we keep the original stepper motor installed, disconnect from the valve, install the valve on the bung and see if it throws a CEL.. However, another member mentioned that it would. I am going to try to put the modified EGR valve in my car now. I dont know how ambitious I'll be. I'll update in a couple of hours.
ok, you are obviously more informed than I am, but I have read how a stepper motor works today and looked over all the information I have at my disposal. It looks to me like this is a very simple circuit in which the ecu will close the circuit on one or two leads at a time. That means it will draw current from pin 2 or pin 5, pin 2, or pin 5 right? I understand the equation for resistance, that's why I asked the resistance between one and three. If you can provide the same resistance as the coil the ecu will still pulse each wire, and will still see the same current on the other side of the circuit that it would if the motor was still hooked up.
depending on what side of the resistor your "y" connection is at determines what resistance the ECU will see on each lead. as long as there is nothing else internal to the valve there is no difference between my drawing and a stepper motor. the only difference is there will be no moving parts. current through an electromagnet is only stepped down by the resistance in the coil right? or am I mistaken in all that I say here

I have taken a couple semesters of physics, and dabble in electronics. you are a little beyond that, right drew? what's your degree? good to be working on something like this with you man, seems like you will be an asset here


