I don't think I need to I believe I can just plot this out logically. You have a spark plug and a coil. One side of the coil goes into the spark plug, the spark plug has only one electrical path and that's into the head. The head can't have a direct path to the other side of the coil if it's connected to +12 volts because that would be a big short of the primary system. So to me that means the other side of the coil would need a path to ground to complete the loop. At least that's how it plays out in my head, but I'm no EE.

 

Here this at least has real electrical symbols, and as you can see the secondary is tied to ground

 

What you've done there is cut and pasted the incorrect diagram for LS1 / LS2 which originated from megasquirt.

The correct diagram is below.

https://www.google.co.nz/imgres?imgu...act=mrc&uact=8


The LS coils are an isolating transformer much like the wasted spark coils but different from the toyota coils which are an auto transformer.

If you don't know what an auto transformer is ...look it up on wiki.

https://en.wikipedia.org/wiki/Autotransformer


If you don't understand the basic concept, you're not in a position to give advice to others who similarly don't understand.

 

I don't know where it came from I just googled coil pack diagram. I will say it makes 1000 times more sense then any of the crap you post.

 

The return path for the toyota coils ....as I said above.........it's the same as it always has been since the invention of kettering ignition.

It's from the engine block to the battery negative terminal, to the battery positive terminal and back to the coil positive terminal.
With points ignition (same as electronic) , it can't return any other way because the points are open when the spark occurs.

 

Moving on....
Has anyone tested the voltage at each ignition connector at 7000 rpm? We will need a fast reading meter since the dwell time is probably around 2.5 ms.

 

The tool for it is an oscilloscope.


Yes I've done lots of testing over a long period of time.

 

And what voltage does it sag to? What is peak voltage and what currents did you see under load?

 

There's lots and lots of variables.

Voltage where?
At what pin under what conditions?
Voltages and currents vary with time and vary with battery voltage, plug gap, coil energy, engine RPM, cylinder pressure and AFR.

 

At the COP running at 7000 rpm on stock evo 9 block with bolt-ons. Gap is 0.020". Battery voltage is 14.0-14.2.

 

Its like you use Google to look up words to throw out but have literally no idea what you are saying... How can there be a path between the negative and positive terminals of a battery? You know what that's called.... A short, if one existed it would start a fire. Don't believe me, go take a piece of wire and touch both terminals and see what happens...

 

Gents

So far the discussion appears somewhat healthy. Please keep it above board & respectful


Thanks,

 

No it will not short out. What you are saying with the wire or even a piece of metal is overriding the battery not going through it. Going through it does not cause a short. If there could be no connection whatsoever between the two terminals, then by removing the negative but leaving the positive in place the car would start.




As I said you need to find a used ignition coil and disassemble it as you got it wrong and only by doing that you will be convinced.









Marios

 

Thinking further, the spark plug won't allow a 12V connection. So that circuit is dead. So the spark energy has to come back somehow.

Corrected. Deleted to avoid confusion.

 

Yah again I'm not an EE just a dude trying to understand how **** works. I do understand batteries can be a series element in a circuit. That's really why I want to see a data sheet, I'm not gonna buy and cut up a coil because I don't care that much lol. I'll happily read a data sheet and eat crow if I'm wrong.