Want to remove/disable your rear O2 sensor without a CEL? Here's how..
edit i just re-read the whole thread - you're essentially running the same as the rest of us. 2 100/10W in parallel for good heat dissipation.
didn't find anyone in this thread that has a 10 or 12K working.
Last edited by EvoBroMA; Jun 30, 2008 at 10:08 PM.
SOB the 2x 50ohm 10W resitors works for the CEL fix but damn it gets hot! Is it even safe to keep in the car?I wanna tuck it under the carpet under the passenger seat, but I don't need a fried evo!
you can always try and use just one of the 50s... it will make less heat than 2.

I have been running the dual resistors at a 25 ohm load in a metal project box which I keep in my glove box and it gets very warm, even with vented holes. I will be adding another 50 ohm resistor is series this weekend to create a 75 ohm load. This should be cool enough to keep in a plastic project box without radiating much heat. The 2 resistors in parallel would only dissipate less than 0.5 watt each and the 50 ohm resistor you'd be adding in series would only dissipate around 2.7 watts. This is compared to your resistors now which are dissipating around 4.1 watts EACH.
Last edited by Jack_of_Trades; Jul 1, 2008 at 03:06 PM.
56D8 is just the rear O2, P0125 is a coolant temp error. Whether or not there is a periphery that specifically cures that I am not able to say. My latest charting of the peripheries hasnt yeilded one yet.
with periphery0 = 56D8 my ecu keeps throwing p0125 error code under same circumstances as cat efficiency error. i guess that's specific to EUDM version, cause i have never seen this behavior in the US models.
my guess is that periphery bits have different effects in different market ecus, so it can't be completely disabled with periphery value on EUDM... and probably there should be some sort of subroutine patch to address the issue. can anyone advice if tephra rom fixes the problem, please?
For all who are interested. I found a single 5 watt 75 ohm resistor, +/-5% tolerance for $0.70 HERE. I just ordered one myself and the shipping costs are usually nothing at all so I'd expect for it to be less than $2.00 shipped.
in general, power is directly correlated to heat, so its a good assumption that the more power, the more heat.
Ohms Law: E=IR --> I = E/R
Watts Law: P=IE --> P=EE/R (P is inversely proportional to R)
The larger R is the smaller P is, so -
R = 50 || 50 = 25 Ohms
vs
R = 75 Ohms
clearly the 75 will generate less heat.
but! that doesn't account for heat sinking and power capability.
the 75 is only rated for 5W. whereas the 50s are 10W a piece.
Code:
Ptotal P/r %W/r 50 || 50 : 7.84W 3.92W 39% 50 : 3.92W 3.92W 39% 75 : 2.61W 2.61W 52%
is a 75/5W cooler then a single 50/10W ? theoretically the 50 should generate more heat, but i honestly couldn't tell you because the 75 is at 52% of its limit. you'll need to wire both up to a power supply and use a heat gun to get a definitive answer.
I can tell you however that the 50 should last longer than the 75, but practically it shouldn't matter. the 75 is probably the best answer.
Last edited by EvoBroMA; Jul 2, 2008 at 04:25 PM.
I just got in my 75 ohm resistor and bench tested it at 14.00 volts for 30 minutes and it holds steady at 250*F. A single 50 ohm 10 watt ceramic resistor from radio shack topped out a 220*F on the bench which is cooler but it has 4 times the footprint as the 75 ohm resistor which means it will radiate a larger area of heat.
Last edited by Jack_of_Trades; Jul 8, 2008 at 09:05 PM.
Any news on how close they are?You guys have already answered my Mitsu prayers with that damn cel,im going in for inspection this week lets see if it passes.Can i check to see if the readiness check is working with Scantech?
scantech does tell you what readiness tests pass. they pass no problem with the resistor, or o2 sensor in, as long as you haven't unset the periphery bits.
Radioshack didn't have much to work with so I purchased a 10ohm 10W ceramic pair. Plugged one in and it still threw the CEL. Then tried running them in parallel and still failed. I suck at this.
hmmm lets see...
P = E*E/R = 14 * 14 / 10 = 19.6W
so you're putting 20W through a 10W resistor. thats a great way to burn it out, or start a fire.
and then you're putting 2 in parallel, which i said previously doubles your heat output, and current draw.
you should really leave the experiments to someone who knows the basics. or use one of the setups that have already been verified to work.
Last edited by EvoBroMA; Jul 10, 2008 at 01:27 PM.




